Mathematics
10 Online
OpenStudy (anonymous):
find formulae for fogoho ?
f(x)=x power 2 + 1 , g(x)=1/x , h(x)=x power 3
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OpenStudy (anonymous):
\[
(f\circ g\circ h)(x) = f(g(h(x))) = f(g(x^3))=f\left(\frac{1}{x^3}\right) = \left(\frac{1}{x^3}\right)^2+1
\]
OpenStudy (anonymous):
it is a answer ?
OpenStudy (anonymous):
I dunno.
OpenStudy (anonymous):
Does it looks like the answer?
OpenStudy (anonymous):
no think next step is
1/x power 5 + 1
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OpenStudy (anonymous):
what you say?
OpenStudy (anonymous):
How do you get power 5?
OpenStudy (anonymous):
\[
(x^3)^2 = (x^3)(x^3)
\]
OpenStudy (anonymous):
because in multiplications powers are add so 3+2 = 5
OpenStudy (anonymous):
Yeah, but you're multiply \(x^3\) and \(x^3\). So it is 3+3
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OpenStudy (anonymous):
no i think its x power 5
OpenStudy (anonymous):
Okay do you agree with this: \[
x^a\times x^b = x^{a+b}
\]
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
Do you agree with this: \[
(x^a)^2 = x^a \times x^a
\]
OpenStudy (anonymous):
no x power 2a is the answer what you say?
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OpenStudy (anonymous):
I say they're the same damn thing.
OpenStudy (anonymous):
If a = 3, then 2a = 6. 2a is not 5
OpenStudy (anonymous):
oh ya right so sorry its my mistake
OpenStudy (anonymous):
next step is 1/x power 6 +1 ?
OpenStudy (anonymous):
yeah.
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OpenStudy (anonymous):
1+ x power 6 / xpower 6 ?
OpenStudy (anonymous):
i think this is the answer ?
OpenStudy (anonymous):
r u there ?
OpenStudy (anonymous):
\[\left(\frac{1}{x^3}\right)^2+1=\frac{1}{x^6}+1=\frac{x^6+1}{x^6}\]
OpenStudy (anonymous):
1+x power 6 / x power 6 is right
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OpenStudy (anonymous):
if you mean (1 + x^6)/x^6 then yes :)
OpenStudy (anonymous):
you mean i'm correct ?
OpenStudy (anonymous):
if 1 + x power 6 is on top then yes :)
OpenStudy (anonymous):
thanks