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If F(x) = f(xf(xf(x))), where f(1) = 5, f(5) = 6, f '(1) = 3, f '(5) = 4, and f '(6) = 5, find F '(1).
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First use the chain rule to find \(F'(x)\)
yes I used the chain rule and the answer I got was 60, is that correct?
Hell if I know. Show your work maybe?
f ' {1f[1f(1)} times f '[1f(1)] f ' { f[f(1)} times f '[f(1)] times f '(1) f '{f[5]} times f '[5] times f '(1) f '{6} times f '[5] times f '(1) 5 times 4 times 3 = 20 times 3 = 60
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