find formulae for fogoh f(x)=1/1+x , g(x)=3root x , h(x)=1/x power 3
first find goh (x),can u ?
no
goh means replace each x in the function g with 1/x
So do that and post your result.
goh (x) can be found by replacing 'x' in g(x) by h(x)=1/x^3
f{g(1/x^3)}
Replace x in the function f with that result and you will be done except for simplification
see this : when i replace 'x' in g(x) by 1/x^3, i get goh(x) = \(3 \sqrt{1/x^3}=3 \sqrt{x^{-3}}\) got this ?
can i show my whole solution then you tell me
sure, if incorrect, we'll spot the error.
ok wait for a while
f [ g {h(x) } ] f [ g (1/x^3) ] f [ 3root 1/x^3 ] f [ 3 root x power -3 ] tell me is this ans ?
thats just \(f(3\sqrt{x^{-3}})\) you need to evaluate it by replacing x by \(3\sqrt{x^{-3}}in f(x )\)
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