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Calculus1
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OpenStudy (anonymous):
find formulae for fogoh
f(x)=1/1+x , g(x)=3root x , h(x)=1/x power 3
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hartnn (hartnn):
first find goh (x),can u ?
OpenStudy (anonymous):
no
OpenStudy (mertsj):
goh means replace each x in the function g with 1/x
OpenStudy (mertsj):
So do that and post your result.
hartnn (hartnn):
goh (x) can be found by replacing 'x' in g(x) by h(x)=1/x^3
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OpenStudy (anonymous):
f{g(1/x^3)}
OpenStudy (mertsj):
Replace x in the function f with that result and you will be done except for simplification
hartnn (hartnn):
see this :
when i replace 'x' in g(x) by 1/x^3, i get
goh(x) = \(3 \sqrt{1/x^3}=3 \sqrt{x^{-3}}\)
got this ?
OpenStudy (anonymous):
can i show my whole solution then you tell me
hartnn (hartnn):
sure, if incorrect, we'll spot the error.
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OpenStudy (anonymous):
ok wait for a while
OpenStudy (anonymous):
f [ g {h(x) } ]
f [ g (1/x^3) ]
f [ 3root 1/x^3 ]
f [ 3 root x power -3 ]
tell me is this ans ?
hartnn (hartnn):
thats just \(f(3\sqrt{x^{-3}})\)
you need to evaluate it by replacing x by \(3\sqrt{x^{-3}}in f(x
)\)
OpenStudy (mertsj):
|dw:1362258366268:dw|
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