Question

Lead(II) sulfide, PbS, reacts with oxygen gas to produce lead(II)oxide and dioxide. If 0.500 moles of O2 were consumed using this chemical reaction, how much of lead(II)would be produced?

Answer 1

helpp pleasee..

Answer 2

Start by writing out a balanced chemical equation. Can you do that?

Answer 3

I really cant.

Answer 4

Try it. I'm here to help.

Answer 5

Like i cant I have no idea...srry../.\

Answer 6

Try it. There's no punishment here if you are wrong. Just try! It's the best way to learn.
Here are the elements and compounds you have

1. lead oxide
lead= Pb
oxide = oxygen = O
Sulfide = S
Sulfur dioxide = SO2

the "di" in oxide means there are TWO oxygens. Hence, SO2

Now, try and write the chemical equation. It's essential that you know this because your next step is to balance the chemical equation. Both of these steps are the meat and potato to solving this problem. Once you have these, the problem is easy.

Answer 7

NOTE: Also the (II) means that the lead carries a + charge of 2. Natuarally, oxygen, too, carries a -2 charge.

Answer 8

okay would it be....PbS+O2-->PbO..?

Answer 9

Yes. I think you're missing the "dioxide" but i think you mean sulfur dioxide? Because the sulfer is missing in your products. It doesn't just "disappear"

Answer 10

So your chemical equation is partially correct
\[PbS + O_2 \rightarrow PbO + SO_2\]

Answer 11

Oh alright I see

Answer 12

Now, your next step is to balance the chemical equation. Because if you notice, you have two oxygens on the left, and THREE on the right. It needs to be equal amounts of products and reactants on both sides. Here is how you can go about this. Make a table

LEFT SIDE:
Lead (Pb) = 1
Sulfur (S) = 1
Oxygen (O) = 2

RIGHT SIDE:
Lead (Pb) = 1
Sulfur (S) = 1
Oxygen (O) = 3

Your task is to make it even by putting some number in front of the element to make them equal amounts. Remember that they follow the distributive property, so if you say 3 moles of O2 that means you have a total of SIX. because 3 x 2 = 6
And if you change the left side, you must also change the right side. So now you have six oxygens on the left, if you put a 3 in front of SO2 you now have 3 sulfur, and 6 oxygen. You have six oxgens!, but now unequal amount of sulfur. So you have to now add some number to the product side. do this until you find equal amounts. I think you can also have fractional numbers too which is what it looks like for this

Answer 13

okay the balanced equation would be 2 PbS + 3 O2 = 2 PbO + 2 SO2..RIGHT?

Answer 14

Yes, correct! Good job. Now, identify with what you're given and what you want.

GIVEN:
0.500 moles of O2

WANT:
amount of PbO produced. This is referring to amount, so you would want grams!

Next step, identify a "plan"

so your plan would be

moles O2 -> moles PbO -> g of PbO
This is why i said it's important to have your balanced chemical equation. Starting with \[0.500 moles O_2 \times \frac{ 2 moles( PbO) }{ 6 moles (O_2) } = moles (PbO)\]

Now, molar mass (which can be found on the periodic table for each individual element) is defined by grams per mole or: \[\frac{ grams }{ moles }\]
So do the same thing now that you have moles. use this method (called dimensional analysis) to cross cancel and find grams of pbO

Answer 15

Okay ill try it...thank you so much for the help.

Answer 16

okay so I need to find the moles of PbO?

Answer 17

Yes. Find the moles of PbO using the method i showed you
look at the balanced chemical equation and use that as a reference as to what you're multiplying and dividing by to get moles.
It's the same thing as: \[0.500x \times \frac{ 7y }{ x } = 0.500 \times 7y = ...\]

Answer 18

okay i did that wrong..i got it now thanks

Answer 19

37.0512 of lead would be produced.