Solve: 3^2 - 2^2 / square root of 4 + square root of 49 using BIDMAS. Cheers

Question

mertsj · Answer

$$\frac{3^3-2^2}{\sqrt{4}+\sqrt{49}}$$

anonymous · Answer

It is not written as a fraction

anonymous · Answer

You have to use BIDMAS in the process

mertsj · Answer

9-4/2+7=
9-2+7=7+7=14

anonymous · Answer

Why can't it be 9-9=0 if addition and subtraction according to BIDMAS is of equal priority?

mertsj · Answer

Because 4/2 means 4 divided by 2 and you must do the division before the addition and subtraction.

anonymous · Answer

what the monkey is a bidmas?

mertsj · Answer

brackets, indices, division multiplication, addition, subtraction

anonymous · Answer

oooh
sort of like "please excuse my senile aunt sally"

mertsj · Answer

Precisely.

anonymous · Answer

That wasn't my question. I said why did you do subtraction before addition?

anonymous · Answer

If you did it the other way you would have got 9-9=0

anonymous · Answer

$$3^2 - 2^2 \div (\sqrt{4}) + \sqrt{49} \implies 9 - 4 \div 2 + 7$$

According to BIDMAS rule, here you will divide first...

anonymous · Answer

I know that part but why subtract and then do the division when it's supposed to be the opposite. Can't it be 9-9=0?

aravindg · Answer

what is I in BIDMAS ?

aravindg · Answer

Oh its above :P ....i got the same doubt as satellite ..we usually use the term BODMAS

hartnn · Answer

it can't be 9-9 because the order of operation (evaluation) is from left to right.
so, 9-2 will be evaluated first, not 2+7