Let $\Large f(x) = \dfrac{2x^3+4x^2-9}{x-3}$ and s(x) be the slant asymptote of f. Find the value of s(-2).

How can I find the slant asymptote?

Question

Let $\Large f(x) = \dfrac{2x^3+4x^2-9}{x-3}$ and s(x) be the slant asymptote of f. Find the value of s(-2).

How can I find the slant asymptote?

geerky42 · Answer

Is s(x) supposed to be linear function or can it be quadratic function?

nory · Answer

I think you are supposed to divide the top by the bottom first.

anonymous · Answer

$$
\lim_{x\to \infty }|f(x) - L| = 0
$$

geerky42 · Answer

This is what I did and I got 2x²+10x+30. I ignored remainder because it is unnecessary.

anonymous · Answer

Does it work on this formula?

geerky42 · Answer

What is that?

anonymous · Answer

Definition of slant asymptote

geerky42 · Answer

Never seen this formula... what does L represent?

anonymous · Answer

Where L is the expression of the slant asymptote.

geerky42 · Answer

Sorry, I don't get it. I rather solve it algebraically.

geerky42 · Answer

s(x) = 2x²+10x+30 right?

anonymous · Answer

|dw:1362277797948:dw|
Yes.

geerky42 · Answer

So s(-2) = 8-20+30 = $\boxed{18}$.