hi i need help with these questions on MIXED EXPRESSIONS AND COMPLEX FRACTIONS i have the question in links 1. https://media.glynlyon.com/g_alg02_2012/5/276.gif a) a-b b) a - b / a c) 0 2. https://media.glynlyon.com/g_alg02_2012/5/272.gif a) 0 b) 1 c) x + y / x - y 3. https://media.glynlyon.com/g_alg02_2012/5/258.gif a) xy / x + y b) 2x^2 + xy / x + y c) -x^2 / x + y 4.https://media.glynlyon.com/g_alg02_2012/5/254.gif a) 187 / 25 b) 109 / 25 c) 384 / 25 5. https://media.glynlyon.com/g_alg02_2012/5/270.gif a) y / x b) x / y c) xy 6. https://media.glynlyon.com/g_alg02_2012/5/259.gif a) 1 / m b) 2m - 1 / m c) 2m^2 - 1 / m 7. https://media.glynlyon.com/g_alg02_2012/5/255%20copy.gif a) x + 1 / x b) x^2 + 1 / x c) 2x + 1 / x
1 is A
@ambius giving worked out direct answers is agaist openstudy COC Refer http://openstudy.com/code-of-conduct Instead help the asker get to the solution being a guide along the answering process. Thanks
@AravindG; Sorry, I will remember that.
thanks for understanding. Happy Openstudying !
your work helped ambius could you figure out the other awnsers
@MomoSwag1995; if nothing else, the first one is only an example. Remember, if you are given a list of solutions, you can make one side of the equation equal to the other, and then simplify. You don't necessarily have to choose the more complicated solution... for example, with #2, I would start out with making the equation equal to (A), which is 0. For example: \[\frac{\frac{3x+y}{x-y} - 3}{1-\frac{x-3y}{x+y}}=0\] By setting the right side to zero (because were are testing to see whether or not 2A is the answer), we can quickly simply a large part of the expression and very quickly tell whether or not the right side can equal the left.
ok thanks , were you able to figure out 3- 7
Lol, no. I only got the first two so far, but the other ones shouldn't be much harder.
ok your still woking on them?
Well, I can do a few more I guess.
Please Please
So for number 3, what expression do (almost) all the terms have in the denominator, including the answers?
x
close... it's x plus another variable added to it.
2x
good guess... however, that's not quit it. If you look at all the potential answers, what's in their denominator?
*quite, lol
x+y lol
Good! so, if your going to simplify both sides; what are you going to multiply by?
x+y
so the awnser is a) xy / x + y
??
Yeppers!
And you see how xy/(x+y) was the easiest one to start out with? lol. You can use process of elimination; when you discover the easy ones don't work, by process of elimination, you can determine what the answer is without doing the hardest one, lol
thanks , can you be my tutor lol JK
ok can you help me with the last 4 if it ok with you if not i can totally understand
yeah, I can help. I just may need a minute to look at it.
4. https://media.glynlyon.com/g_alg02_2012/5/254.gif a) 187 / 25 b) 109 / 25 c) 384 / 25 5. https://media.glynlyon.com/g_alg02_2012/5/270.gif a) y / x b) x / y c) xy 6. https://media.glynlyon.com/g_alg02_2012/5/259.gif a) 1 / m b) 2m - 1 / m c) 2m^2 - 1 / m 7. https://media.glynlyon.com/g_alg02_2012/5/255%20copy.gif a) x + 1 / x b) x^2 + 1 / x c) 2x + 1 / x
you can take all the time you want i will be here
Okay! So #4 is nice and easy... it's a mixed fraction. Remember that when dealing with mixed fractions, it's easier to convert it to a full fraction before working with it.... lol
ok
So, if your fraction is in mixed form like so: \[A\frac{b}{c}\] to convert it to a full fraction (aka improper fraction): \[\frac{(A*c)+b}{c}\]
(7*25)+12 / 25 ???
exactly. What does that give you?
4387/25
Hmmm... I think there was a typo in your calculator, lol. Try again. :)
c) 384 / 25
So, 7*25 = 175 .... 175+12 = 187... so your answer is?
187 / 25 "saying duh to myself"
lol, it happens to even the pros. They had to create a lense for the hubble telescope that cost them millions because they forgot light refracts in air. They've even had landers miss their targets for forgetting to convert imperial to metric...
so, no problem, right? lol
onto #5.
yes
okay, so for the next one, it looks like we are going to be multiplying by \[\frac{xy^2}{z^2}\] in order to simplify the expression on the left. If we do this, we'll be leaving \[ \frac{x^2y}{z^2}\] on the left side; so given we want the left side to equal the right, what would be a good expression to start out with on the right?
xy^2
Another way to look at this one is: \[\frac{x^2y}{z^2}=A\frac{xy^2}{z^2}\]
where A is our answer.
ok i see now
so, if A= 5a (or A= y/x) does that give us equal sides?
yes
not quite... because the left and right sides would be: \[\frac{x^2y}{z^2}=\frac{y^3}{z^2}\] what if A= 5b?
not equal
are you sure? \[A=\frac{x}{y}\] \[\frac{x^2y}{z^2}=\frac{x}{y}\frac{xy^2}{z^2}\] What would happen to the power on the right hand side?
*powers
cancel?
\[x*x=x^2\] \[\frac{y^2}{y}=y\] The powers add when multiplied and subtract when divided, right?
yes
so, in this case then, the right side simplifies to a numerator of x^2*y with a denominator of z^2; there the right equals the left, so 5b is the answer.
thank you can you help me with this one i found out how to do 6 & 7 https://media.glynlyon.com/g_alg02_2012/5/277.gif a) -a^2 / b^2 b) 0 c) 1
sure... I can help with one more, lol
ok
So, the easy case to test is 0. If you set the right side of the equation equal to 0, through algebra, can you get the left side to equal the right?
so it 0 right
??
So, one of our possible answers is 5b, which is zero. So if we set the right side of the equation to zero as so: \[(\frac{a}{b}+\frac{1}{a})(a-\frac{a^3}{a^2+b})=0\] And we simplify it as much as possible, can we get the left side to equal the right?
No
Correct; so 5b is not our answer.
it is 0
am i correct
When you said "No, it is impossible to make the left side equal to the right when we start with the right side equal to zero (5b)", you were correct. Our answer cannot be 5b.
So the answer has to be 5a or 5c. Starting with 5b was the easiest. Which would most likely be the next easiest answer to work with? 5a or 5c?
thats no one of the choices
not*
Sorry; I don't mean to be confusing. I mean (a) or (c).
your ok and C
C is correct: \[(\frac{a}{b}+\frac{1}{a})(a−\frac{a^3}{a^2+b})=1\] So, if we simplify this, can we get the left to equal the right?
YES !! :)
just checking the math, lol. You might have been faster than me on this one. :)
Really lol
Yes! your correct! I think you've got the hang of it, lol
Kind Of Lol
I don't think they're easy problems myself; it's very easy to make an algebraic mistake. But as they say, 'practice makes perfect', right? :)
You Got me an A !!thanks
No problem, lol
Im taking Algebra 2 Class Online
Really? Which school?
odessyware
Cool! I was thinking of maybe doing some math coarses online myself; I didn't do too well in math in highschool for a number of reasons (not school related). But as you can see, it's not for a lack of ability, lol
yes you should do it
i did not do well in algebra 2 last semester so for this semster it told my guidence councler just let me take it online
I*
I have this Unit anf 1 more unit left
and*
thank god
lol
Lol
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