Question

(5x^4/4x^2)^2

Answer 1

not quite.

the question appears to be

\[(\frac{5x^4}{4x^2})^2\]

so look inside the brackets

the index law for division says subtract the powers

\[\frac{x^a}{x^b} = x^{a - b}\]

you need to do this

the fraction 5/4 won't change...

what do you get..?

Answer 2

ok hold on I tried a couple times but I got the wrong answer let me try again

Answer 3

@mathmind... I think the brackets are around the entire fraction, not just the denominator

Answer 4

so if you use the index law you get

\[(\frac{5x^2}{4})^2\]


you will need to know about the power of a power law where you multiply the powers.


\[(x^a)^b = x^{a \times b}\]

so you will have

\[\frac{5^2(x^2)^2}{4^2}\]

which you need to simplify

Answer 5

so 25x^4/16 I was doing the multiplying by the power outside the brackets first and Ikept getting ugly answers.

Answer 6

Thank you very much

Answer 7

thats correct...

Answer 8

well if you squared everything 1st you would have had

\[\frac{25x^8}{16x^4}\]

then subtract the powers for the answer you have above.

good luck

Answer 9

I have another one its but im not sure I got 1x^9y^5/9z