Question

evaluate the integral from 0 to pi/2 [(2-sinx)^2dx]

Answer 1

Fisrt, u have to expand this :
(2-sinx)^2 = 4 - 4sin(x) + sin^2 (x)

Answer 2

use the identity to converting sin^2 (x) = (1 - cos(2x))/2 = 1/2 - 1/2*cos(2x)

Answer 3

so, (2-sinx)^2 = 4 - 4sin(x) + 1/2 - 1/2*cos(2x)
= 9/2 - 4sin(x)- 1/2*cos(2x)
now, u can integrate each term one by one just use the basic formula in integration

Answer 4

ohhhh got it. thanks :)

Answer 5

you're welcome :)