PLEASE ANYONE HELP! Given the diagram below with ∠5 ≅ ∠6 and ∠6 ≅ ∠4, prove that AD||BC Use the two-column proof format. Picture attached.
Given: Diagram as shown; ∠5 ≅ ∠6 and ∠6 ≅ ∠4 Prove: SegmentAD || Segment BC
Statements ---------- 1. ∠5 ≅ ∠6 2. ∠6 ≅ ∠4 3. Therefore, <5 ≅ <4 4. Segment AD || Segment BC
Check the statements. Your Task: Write the reasons. I'll check them if you like after you finish.
@RH
THANK YOU SO MUCH! I'll write them now! THANK YOU THANK YOU THAAAANK YOU! :)
Reasons: 1)Given 2)Given 3)Angle addition postulate 4)CPCTC (I am not sure about this :(! )
@Directrix
Reasons 3 and 4 are not correct.
For reason 3, look at statements one and two. Two angles congruent to the same angle are congruent to each other is known as which property?
Is it definition of congruence?
I am sorry for bothering you :(
and thank you for helping!
The property begins with the letter "T"
m∠4 = m∠A + m∠B - Exterior Angle Theorem can this be added to the proof?
and ends with "of Congruence." So, you are on the right track.
the transitive property of congruence?
>m∠4 = m∠A + m∠B - Exterior Angle Theorem can this be added to the proof? No. We are not doing anything with triangles. We are working with parallel lines.
>the transitive property of congruence Yes, this is correct for reason 3.
Thank you! :)
Now, this > 4. Segment AD || Segment BC Look at the diagram. What kind of angles are angles 5 and 4 with respect to segments AD and BC and transversal AB?
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