Question

Binomial expansion..

(X squared -2y) to the 5th

Answer 1

@Hero

Answer 2

\[(x^2-2y)^5\]
confirm please

Answer 3

\[(x^2-y)^5= x^{10}-10x^8y+40x^6y^2-80x^4y^3+80x^2y^4-32y^5\]

Answer 4

that's your binomial expansion

Answer 5

ok how did you start off with X to the 10th

Answer 6

ok have u heard of pascal's triangle?

Answer 7

yes i have

Answer 8

and the 5th would be 1 5 10 10 5 1 right?

Answer 9

\[(x^2)^5\]

Answer 10

yes u are write but look at the above...

Answer 11

oh you multiply

Answer 12

yes exactly

Answer 13

u have to put the whole term to the highest power...

Answer 14

ok but one like for the others you multiply them as well cause i remeber they said something about raising them

Answer 15

yes u raise one power and reduce the other for the other term

Answer 16

i was talking about the first term

Answer 17

ok but would that be the final answer cause i saw my teacher do something else im not sur though

Answer 18

well do u want the detailed solution?

Answer 19

plugging in the binomial general formula?

Answer 20

yes

Answer 21

ok i will show u how to do that

Answer 22

ok

Answer 23

\[(a+b)^n=\sum_{k=0}^{n}\left(\begin{matrix}n \\ k\end{matrix}\right)a^{n-k}b^k\]

Answer 24

wow well that looks a bit confusing

Answer 25

hehehehe

Answer 26

ok i will use the normal way

Answer 27

ok please

Answer 28

\[(a+b)^n=a^n+C^{n}_1a^{(n-1)}b+C^{n}_2a^{(n-2)}b^2+...+C^{n}_{n-1}ab^{(n-1)+b^n}b\]

Answer 29

do u know this form...

Answer 30

in this picture instead of a you plug in x^2, and instead of b you plug in -y

Answer 31

ok well im gonna try working on it, thanks.