Question

a chemist wants to obtain 80 liters of a solution that is 12% hydrochloric acid.how many liters of 10% hydrochloric acid solution and 20% hydrochloric acid should be mixed?

Answer 1

This looks familiar. Couldn't you solve the system of equations I worked out for you?

Answer 2

no, i tried but i couldn't :/

Answer 3

Let A = required number of liters of 10% hydrochloric acid solution.
Let B = required number of liters of 20% hydrochloric acid solution.
A + B = 80 .........................................(1)
Number of liters of hydrochloric acid in required solution = 80 * 0.12 = 9.6
0.1A + 0.2B = 9.6 .............................(2)
If we multiply both sides of equation (2) by 5 we get
0.5A + B = 48 ...................................(3)
Subtracting equation (3) from equation (1) gives
0.5A = 32 ...........................................(4)
Can you solve equation (4) to find A and then substitute the value of A into equation (1) to find B?

Answer 4

32/0.5=64 and 80-64=16 so 10 percent one is 16 and 20percent one is 64 ?

Answer 5

thank you so much!!

Answer 6

the answer is wrong :/

Answer 7

A is the amount of 10% solution which is 64 liters.
B is the amount of 20% solution which is 16 liters.

Answer 8

okay its right thank you so much again!!

Answer 9

You're welcome :)