Find the function f that has the derivative f'(x)=4x+1 and whose graph passe through the point (1, 0).

Question

moonlitfate · Answer

I was able to figure out par of the main function, but I think there's something missing.  I have f(x) = 2x^2 + x ; since that would give f'(x) = 4x+1...

anonymous · Answer

2x^2+x-3

moonlitfate · Answer

I definitely missed something, the -3 on the end. Not sure where that came from

anonymous · Answer

ummm i definitely just started plugging in random numbers until the graph crossed at (1,0) lol but the derivative of -3 is zero so it's not gonna show up in the equation $$f \prime(x)=4x+1$$

campbell_st · Answer

you have the correct indefinite integral but it needs a constant

$$y = 2x^2 + x + C$$

now use the point (1, 0) to find C

0 = 2(1)^2 + 1 + C

C = -3

anonymous · Answer

but if i had known this equation that's how i would've done it lol

moonlitfate · Answer

I definitely need to remember that!  I always forget the small easy steps.