If xy + 8e^y = 8e, find the value of y'' at x =0.

Attempt:
I know what the second, and first derivative will look like. I just don't know how to go about with plugging in the x=0.
If xy + 8e^y = 8e, find the value of y'' at x =0.

Attempt:
I know what the second, and first derivative will look like. I just don't know how to go about with plugging in the x=0.
@Mathematics

Question

If xy + 8e^y = 8e, find the value of y'' at x =0.

Attempt:
I know what the second, and first derivative will look like. I just don't know how to go about with plugging in the x=0. 
If xy + 8e^y = 8e, find the value of y'' at x =0.

Attempt:
I know what the second, and first derivative will look like. I just don't know how to go about with plugging in the x=0. 
@Mathematics

anonymous · Answer

@amytincan what r u getting the value of y''? After knowing the value of y'' , it will be possible to plug the value of x

anonymous · Answer

I'm not doing so well on this I'm at y'

$$y'=-y/(x+8e^yln8e)$$

anonymous · Answer

i m getting y' = -y/x+8e^y

anonymous · Answer

Niksva, I am stuck on the denominator, apparently I do not know how to get the derivative of 8e^y.   Is the formula for this portion supposed to be d/dx[a^g(x)]=a^g(x)lna(g'x)?

anonymous · Answer

no for the exponential function we follow the formula given below
d/dp (e^q) = e^q dq/dp
we write the exponential function as it is

anonymous · Answer

But that's a particular case of @amytincan 's Formula... 
when a=e @niksva ...
 Because lne =1 :-)

anonymous · Answer

omg my fault sorry @amytincan and thanx @salonigupta95 
but i have done the first derivative right

anonymous · Answer

Yeah... I agree in that ...

anonymous · Answer

it seems second derivative is going to get more complex

anonymous · Answer

Is it fine???
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