what is the solution set of "x^2-0

Question

what is the solution set of "x^2-0 < 0"

anonymous · Answer

I'm thinking its...
-9<x<9

raden · Answer

Hint : the square of a real number cant be negative

anonymous · Answer

my options are -33 x<-9 or x>9

anonymous · Answer

Positive

anonymous · Answer

x^2 is the same thing as x squared

anonymous · Answer

that would be it hero, it fits with the solution choices

anonymous · Answer

I'm realizing that I'm positing it correctly

anonymous · Answer

@matineesuxxx , what do you think?

raden · Answer

maybe ur question is x^2 - 9 < 0
because if like the first, no solution satisfies for x

anonymous · Answer

if that was my question, what would the answer be?

anonymous · Answer

No, I want you to help me FIND the answer

anonymous · Answer

it's from a book

anonymous · Answer

this is a difference of squares. so $$x^2-3^2 = (x-3)(x+3)$$ now is a negative or positive? once you determine that you know which way the graph opens. now you know a rough drawing of the parabola then you also know when it crosses the x axis.

anonymous · Answer

thank you!

anonymous · Answer

no problem:)

anonymous · Answer

1st of all I wouldn't exactly call this an argument.  Second of all, I didn't post the wrong question.

anonymous · Answer

oh jeeze, I read your post, hero about it being x^2-9 and thought it was cat posting it. and katmole, if the question is $$x^2-0<0$$ then there are NO solutions.