Question

10^(3x-8)=2^(5-x)

Answer 1

try taking the natural log of both sides of the equation. that would allow you to take down the exponents using log rules.

Answer 2

I don't understand log rules

Answer 3

Taking logs:
\[\ln10^{(3x-8)}=\ln2^{(5-x)} \]Take the exponents down:
\[(3x-8)\times \ln10 = (5-x)\times \ln2\]Solve for x!