Mathematics
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OpenStudy (anonymous):
Describe the vector as an ordered pair. Round the coordinates to the nearest tenth. The diagram is not drawn to scale.
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OpenStudy (anonymous):
OpenStudy (anonymous):
Remember SOH CAH TOA?
OpenStudy (anonymous):
The y coordinate is the opposite side and the x coordinate is the adjacent side.
OpenStudy (anonymous):
so i would use tangent?
OpenStudy (anonymous):
No....
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OpenStudy (anonymous):
You are given hypotenuse.
OpenStudy (anonymous):
For the x coordinate, you know the adjacent side is x, along with the hypotenuse...
OpenStudy (anonymous):
This is CAH,
OpenStudy (anonymous):
For the y coordinate, it's opposite side is y, thus SOH
OpenStudy (anonymous):
im confuced so i would use sine and cosine?
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OpenStudy (anonymous):
Basically: \[
\sin(69^\circ) = \frac{y}{54} \\
\cos(69^\circ) = \frac{x}{54} \\
\]
OpenStudy (anonymous):
You have two variables, so you need two equations. It wasn't going to happen in a single equation.
OpenStudy (anonymous):
Using \[
\tan(69^\circ) = \frac{y}{x}
\]would not help you out that much.
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
Even though it is true.
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OpenStudy (anonymous):
Any more questions?
OpenStudy (anonymous):
not yet
OpenStudy (anonymous):
@wio i found the sine and cosine so what now?
OpenStudy (anonymous):
Did you solve for x and y?
OpenStudy (anonymous):
yes i believe
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OpenStudy (anonymous):
Then you have your answer.
OpenStudy (anonymous):
for the two equations you gave i got 50.4 and 19.4
OpenStudy (anonymous):
are those my coordinates?
OpenStudy (anonymous):
Yeah.
OpenStudy (anonymous):
y is obviously the longer one.
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OpenStudy (anonymous):
so its (19.4 , 50.4)