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Mathematics 17 Online
OpenStudy (anonymous):

Describe the vector as an ordered pair. Round the coordinates to the nearest tenth. The diagram is not drawn to scale.

OpenStudy (anonymous):

OpenStudy (anonymous):

Remember SOH CAH TOA?

OpenStudy (anonymous):

The y coordinate is the opposite side and the x coordinate is the adjacent side.

OpenStudy (anonymous):

so i would use tangent?

OpenStudy (anonymous):

No....

OpenStudy (anonymous):

You are given hypotenuse.

OpenStudy (anonymous):

For the x coordinate, you know the adjacent side is x, along with the hypotenuse...

OpenStudy (anonymous):

This is CAH,

OpenStudy (anonymous):

For the y coordinate, it's opposite side is y, thus SOH

OpenStudy (anonymous):

im confuced so i would use sine and cosine?

OpenStudy (anonymous):

Basically: \[ \sin(69^\circ) = \frac{y}{54} \\ \cos(69^\circ) = \frac{x}{54} \\ \]

OpenStudy (anonymous):

You have two variables, so you need two equations. It wasn't going to happen in a single equation.

OpenStudy (anonymous):

Using \[ \tan(69^\circ) = \frac{y}{x} \]would not help you out that much.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Even though it is true.

OpenStudy (anonymous):

Any more questions?

OpenStudy (anonymous):

not yet

OpenStudy (anonymous):

@wio i found the sine and cosine so what now?

OpenStudy (anonymous):

Did you solve for x and y?

OpenStudy (anonymous):

yes i believe

OpenStudy (anonymous):

Then you have your answer.

OpenStudy (anonymous):

for the two equations you gave i got 50.4 and 19.4

OpenStudy (anonymous):

are those my coordinates?

OpenStudy (anonymous):

Yeah.

OpenStudy (anonymous):

y is obviously the longer one.

OpenStudy (anonymous):

so its (19.4 , 50.4)

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