Question

unfoil this. Show the steps

Answer 1

\[y^2+12x-28\]

Answer 2

\[(y+14)(y-2)\]

14-2 = 12
14*-2=-28

Answer 3

how did you know if the 14 went into the first parethesis while -2 went into the second

Answer 4

It doesn't matter, you can swap as long as the coefficients of y are the same.

Answer 5

it really doesn't matter which way you put it.

you can have

(y-2)(y+14) and it would be the same

kind of like

(3-2)(3-1) is the same as (3-1)(3-2)