In a given experiment 102 g of PCl5 was placed in an empty 1.0 L container. Equilibrium was established with the following equation PCl5---- PCl3+Cl2 k=1.2*10^-4 How do I find the values at equilibrium?

Question

In a given experiment 102 g of PCl5 was placed in an empty 1.0 L container.  Equilibrium was established with the following equation PCl5----> PCl3+Cl2 k=1.2*10^-4 How do I find the values at equilibrium?

aaronq · Answer

>Write a balanced equation

>Set up an equilibrium expression

>convert mass of PCl5 to moles -> plug into equilibrium expression

anonymous · Answer

I'm not given values for the PCl3 or Cl2

aaronq · Answer

thats what they want you to find, they gave you the equilibrium constant K.

anonymous · Answer

so you would set it up as x^2/ .49-x= .00012?

aaronq · Answer

yep, solve for x

anonymous · Answer

x^2+ .00058x-.0012=0?

aaronq · Answer

doesn't look right

anonymous · Answer

how do i make it into a quadratic?

aaronq · Answer

x^2/(.49-x)= .00012

x^2= .00012(.49-x)

distribute, set equal to zero

anonymous · Answer

x^2+.00012x-.000058?

aaronq · Answer

yep looks better

anonymous · Answer

thanks soo much