Question

Question about probability

Answer 1

i just need help with last one

Answer 2

f

Answer 3

a little confusing because it does not say what the experiment is
is a candy selected from each bowl??

Answer 4

sorry

Answer 5

thats the full question

Answer 6

really?

Answer 7

for the first one i have

GG, GL, GC, GR, LL, LC, LR, CC, CR, RR

Answer 8

for the second one '

PP, PY, PR, YY, YR, RR

Answer 9

it doesn't say
"a candy is selected from each bowl"
or
two candies are selected from a bowl chosen at random
or something??

Answer 10

im not really sure for that one

Answer 11

than you can't really answer can you? or you can assume that it means "select a candy from each bowl"

Answer 12

i guess so

Answer 13

probability that the flavours are the same is 3/10 and the probability that the colors are the same 3/6

Answer 14

lets assume it means "select a candy from each bowl:

Answer 15

is it P(selecting 1 grape from bowl 1) OR P(selecting 1 grape from bowl 2)

Answer 16

thats what i got

Answer 17

then lets do the first one
you have to compute three probabilities

Answer 18

\[\frac{2}{20}\times \frac{6}{20}+\frac{7}{20}\times \frac{5}{20}+\frac{8}{20}\times \frac{2}{20}+\frac{3}{20}\times \frac{7}{20}\]

Answer 19

is it for C ?

Answer 20

no, that is for the first one

Answer 21

are you just doing f, or c-f

Answer 22

oh yeah, that is C

Answer 23

looks like \(\frac{21}{100}=.21\) for that one

Answer 24

so, its the answer for the assumption select a candy from each bowl

Answer 25

yes, your second post which i did not see says you are selecting one from each bowl

Answer 26

ok, what about the d

Answer 27

then it is 1 minus the answer in C

Answer 28

because if they are different, they are not the same

Answer 29

0.79 ?

Answer 30

assuming my calculation above was correct, yes

Answer 31

for the e
i got 7/20 times 2/20

Answer 32

no i don't think that is right

Answer 33

can you help me?

Answer 34

"or" is a union, you add the probabilities, then subtract off the intersection

Answer 35

how?

Answer 36

first is lemon, \(\frac{7}{20}\)
second is cherry \(\frac{2}{20}\)
both \(\frac{7}{20}\times \frac{2}{20}\)

Answer 37

add the first two, subtract the third

Answer 38

oh, ok

Answer 39

for the last one i totally dont get it

Answer 40

probably the notation is throwing you off, it is not that bad

Answer 41

\[P(X=0)\] means you don't get any grape

Answer 42

so, when its 0, its 0

Answer 43

\[P(X=0)=\frac{18}{20}\times \frac{14}{20}\]

Answer 44

didn't get a grape on the first
and didn't get a grape on the second

Answer 45

\[P(X=2)\] means both are grape
\[\frac{2}{20}\times \frac{6}{20}\]

Answer 46

got one on the first try
and got one on the second try

Answer 47

what about x=1?

Answer 48

got one on the first try AND didn't on the second OR didn't on the first AND did on the second

Answer 49

and means multiply, or means add

Answer 50

\[\frac{2}{20}\times\frac{14}{20}+\frac{18}{20}\times \frac{6}{20}\]

Answer 51

is that for x=1 ?

Answer 52

?

Answer 53

im not sure for the last part

Answer 54

for the D it was wrong as the satellite73 explained before

Answer 55

because they are different colors?

Answer 56

because for the first bowl we pick cherry and second bowl we also have to pick cherry bowl + first bowl of rasberry and second bowl of aspberry

Answer 57

because they have same color

Answer 58

coudl you explain d?

Answer 59

are each of the candies different colors.

Answer 60

or are cherry and raspberry different colors.

Answer 61

no they are same

Answer 62

so there are really 3 different collors instead 4

Answer 63

i guss, could you help?

Answer 64

answer is not 1-C

Answer 65

are you selecting one candy for each bowl or two candies from one bowl?

Answer 66

two candies from one i guess

Answer 67

ok, then i think you need to find the following probability.

P(Grape AND Lemon) OR P(Grape AND(Cherry or Raspberry)) OR P(Lemon AND (Cherry or Raspberry))

Answer 68

Find the probability that they are the same color and subtract from 1

Answer 69

grape = purple
lemon = yellow
raspberry and cherry = red


// i think its 19 because you already removed a grape

P(purple and yellow) = P(purple)*P(yellow) = (2/20)*(7/19)



P(purple and red) = P(purple)*P(red) = (2/20) * (11/19)


P(yellow and red) = P(yellow) * P(red) = (7/20)*(11/19)

add them up i think.

Answer 70

what if we are selecting one candy for each bowl

Answer 71

Well that's what the experiment was...select one candy from each bowl and tell the probability that they are different colors.

Answer 72

but i did what you said, answer is wrong

Answer 73

What did you get?

Answer 74

Did you get the other stuff right?

Answer 75

Did you get you sample spaces right?

Answer 76

here is my sample space

Answer 77

Was it correct?

Answer 78

S1={GG,GL,GC,GR,LL,LG,LC,LR,CC,CR,CG,CL,RR,RG,RL,RC}

Answer 79

S2={PP,PY,PR,YY,YP,YR,RR,RP,RY}

Answer 80

grape = purple
lemon = yellow
raspberry and cherry = red

Answer 81

because for the first bowl we pick cherry and second bowl we also have to pick cherry bowl + first bowl of rasberry and second bowl of resberry

Answer 82

So 2/3 was wrong?

Answer 83

resberry and cherry they have same collor

Answer 84

Was 2/3 wrong?

Answer 85

you think its 0.6 ?

Answer 86

Did you get 2/3 before?

Answer 87

no

Answer 88

Look at your sample space. How many outcomes are in the sample space?

Answer 89

16 for first one

Answer 90

Are we talking about colors or flavors?

Answer 91

What is the probability that the two selected candies are different colours?

Answer 92

So we're talking about colors?

Answer 93

yes

Answer 94

D

Answer 95

Then tell me how many outcomes are in the color sample space.