Question

integrate (1-x) ln x dx

Answer 1

by parts

Answer 2

break it up into two integral (ln(x)) and -x(ln(x))

for the second part do a u substitution where u = ln(x); du = dx/x

Answer 3

not sure if parts is necessary @TuringTest

Answer 4

not using the udv = uv - vdu?

Answer 5

I think parts is best here.

Answer 6

yes, use dv=1-x and u=ln(x)

Answer 7

can you show me the solution? i've done mine but it seems incorrect

Answer 8

no we cannot give direct answers here, why don't you try and show us how you do?

Answer 9

its pretty long. but my answer is
ln x [ x - (x^2/2) ] - x - (x^2/4) + C

Answer 10

yeah, u sub wouldn't work since u = ln(x), du = dx/x , x*du = dx.

Answer 11

but that answer is correct :)

Answer 12

oh I think except for a minus sign...
ln x [ x - (x^2/2) ] - x + (x^2/4) + C

Answer 13

thank you!!

Answer 14

welcome :)