Question

if P(E)=0.33, what are the odds against E?

Answer 1

\[\text{Odds against $E$}=\frac{P(E')}{P(E)}=\frac{1-P(E)}{P(E)}\]

Answer 2

why is it not just 1-.33 @SithsAndGiggles .

Answer 3

Can you help me with my question? Please.

Answer 4

1 - .33 is just the probability of "not E". OP is looking for odds.

Answer 5

ok.

Answer 6

it says _ to _ (type integers with no factors)

Answer 7

@mvesling, do you mean as a decimal?

Answer 8

out of 100 you lose 33, win 77

Answer 9

no that is wrong sorry

Answer 10

yes

Answer 11

out of 100 you lose 67, win 33
better

Answer 12

odds against are losses to wins

Answer 13

so 67 to 33?

Answer 14

thx

Answer 15

yes