Question

use dy/dt = kt and derive the formula for y

Answer 1

\[\frac{dy}{dt}=kt\]
\[y=\frac{k}{2}t^2\] i guess, plus some arbitrary constant

Answer 2

dy/dt = kt

(1/k)*dy = t * dt

integral(1/k dy) = integral(t * dt)

//1/k is a constant

(1/k)*integral(dy) = (t^2)/2

(1/k)*y = (t^2)/2

y/k = (t^2)/2

y = (k*t^2)/2

Answer 3

@satellite73 the answer is\[y =y_{0}e ^{kt}\]
which is why i am very confused...