Question

What am I doing wrong?

Answer 1

Didn't mean to hit enter.. oops
A quantity of 65 mL sof a concentrated HCl solution is used to prepare .15 L of a 5.2 M solution. A _______ concentrated solution was used to prepare the .15 M solution?

Answer 2

I took (.065 x 5.2) / .15 and got 2.25 ... but that isn't the right answer. :(

Answer 3

use N1V1=N2 V2 for tthat

Answer 4

Isn't that what I did???

Answer 5

yaa i think

Answer 6

Well, that's not right. & the next one after it is wrong too and I'm pretty sure I am right. :(

Answer 7

instead of 0.65 u should put 15 L their

Answer 8

is it 0.15 L or 15 L and 0.15 M or 15 molar its confusing please add ) before the decimal

Answer 9

Then that just gives you 5.2 which is also not the right answer... That' what I startd doing

Answer 10

it's 0.15 L of 5.2 M solution and 0.15M

Answer 11

Oh and the answer is 12 M ? which doesn't make sense to me because isn't the missing information x mL? or L

Answer 12

yaaa tooo think the same

Answer 13

A =b =C
P=q =X
X=?

Answer 14

What?!

Answer 15

te way to solve it a,bc are known p is known but q
is missing

Answer 16

I've never heard of that =/

Answer 17

5.2 M =0.15 L =65ml
0.15M= missing =X
can u recheck the question
X=missing*5.2 /0.15*0.15 *65

Answer 18

for example
40 g in 1000 ml gives 1M
4 g in 50 ml gives what =50*40/4*1000 *1 =0.5M
it like this kind of problem solving method
but u have missed on quantity in ur question

Answer 19

Idk ... I typed it exactly as it says on the practice test