Solve the equation (x+1)(x+2)(x+3)(x+4)=360
just tell me the starting i'll do the rest
is anyone helpin ??
For this equation, you can expand that left side then move the 360 over to the left. Then you can use synthetic division to try and factor to find the solution.
(y+4)(y+6)=360
where did the x's go? expand: (x+1)(x+2)(x+3)(x+4)
I used a trick
oh... sorry... i'm not familiar with that trick.... can you show me how?
rearranged the terms (x+1)(x+4)(x+3)(x+2)=360 (x^2+5x+4)(x^2+5x+6)-360=0 let y=x^2+5x (y+4)(y+6)-360=0
ok... you'll still need to expand that left side involving y's though....
I solved the equation and got \[{2,-7,\frac{ -5\pm \sqrt{-71} }{ 2 }}\]
oh... you're also looking for complex roots? i was only looking for real ones.. and those first two are the ones i got.... nice work!!!
thanks
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