Question

Find the general solution

Answer 1

\[\frac{ dx }{ dt }=(2-x)\sqrt{1-x}\]

Answer 2

this is what i have so far\[dx=(2-x)\sqrt{1-x} dt\]

Answer 3

\[\frac{ dx }{ (2-x)\sqrt{1-x} }=dt\]

Answer 4

im not sure if that is right though

Answer 5

sure why not?

Answer 6

i get my answer to be \[-2\tan^{-1}(\sqrt{1-x})=t+C\]

Answer 7

i wasn't sure how to do the integral on the left