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Mathematics 15 Online
OpenStudy (anonymous):

what is double integral function? how to solve double integral function?

OpenStudy (anonymous):

Double Integral: http://mathworld.wolfram.com/FubiniTheorem.html You solve in the order of the integral, if dy comes first, you solve as simple integral considering x as constant, after that, solve the integral for dx.

OpenStudy (anonymous):

is the value of dy similar to the value of dx?

OpenStudy (anonymous):

yes they are similar. when you solve the integral according to dy all x values are constant for you. It doesnt matter which one you solve first, dx or dy.

OpenStudy (anonymous):

ahh..ok tnx..can you teach me how to solve this?i have no background in solving this,, \[\int\limits_{0}^{2}\int\limits_{0}^{x ^{2}/2} x/\sqrt{1 + x^2 + y^2} dydx\]

hartnn (hartnn):

if the limits for both the variables were constant, then we can integrate any variable first., but here since the limits of inner integral is not constant, we need to evaluate the inner integral first, limits are y=0 to y=x^2/2 so, since you are integrating w.r.t 'y', treat x as constant, so you have, \(\int\limits_{0}^{2}x[\int\limits_{0}^{x ^{2}/2} 1/\sqrt{1 + x^2 + y^2} dy]dx\) now the inner integral is od the form, \(\int \dfrac{1}{\sqrt{a^2+y^2}}dy\) do you know how to integrate this ?

OpenStudy (anonymous):

why it become a^2?

hartnn (hartnn):

i just took 1+x^2 = constant = a^2 because we have a standard integration formula for, \(\int \dfrac{1}{\sqrt{a^2+y^2}}dy\)

hartnn (hartnn):

then we need to re-substitute back after integration, a^2= 1+x^2 before integrating w.r.t x

hartnn (hartnn):

*after integration w.r.t y,

OpenStudy (anonymous):

in this we are integrating y and we assume as x as constant?

OpenStudy (anonymous):

what do you mean by w.r.t y, ?

hartnn (hartnn):

yes, true, so we'll get answer in 'x' after first integrating w.r.t y (with respect to y)

hartnn (hartnn):

ok, \(\int \dfrac{1}{\sqrt{a^2+y^2}}dy= (1/a)\arctan(y/a)+c\) but then you have to use integration by parts to integrate w.r.t x. so, i suggest we better CHANGE the ORDER of integration, that is, we'll change the limits so that we can first integrate w.r.t 'x' and then 'y'. For that, wee need to plot 2 regions (for 2 limits): (1) y= 0 to y=x^2/2 (2) x=0 to x= 2 can you plot these 4 curves (3 of these are simple straight lines)?

OpenStudy (anonymous):

i'm sorry don't know how to plot this..

OpenStudy (anonymous):

i'm sorry i forgot our previous lessons about that..

hartnn (hartnn):

so, you say you don't know how to plot lines x=0,y=0,x=2 ? i'll help you with y=x^2/2 but if you don't know how to plot those lines, then it'll be very difficult for you to understand this..

OpenStudy (anonymous):

i know this x=0,y=0,x=2 but i don't know y=x^2/2..i'm sorry

hartnn (hartnn):

so, plot these x=0,y=0,x=2 using 'Draw' tool here.

OpenStudy (anonymous):

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