how to do division of hexadecimal numbers?
like 57F6D by B9?

Question

how to do division of hexadecimal numbers?
like 57F6D by B9?

anonymous · Answer

@shevron

anonymous · Answer

it should give you 79b

anonymous · Answer

how?

anonymous · Answer

@hartnn

anonymous · Answer

Dividing numbers work the same for any base

anonymous · Answer

i wanna know the method

anonymous · Answer

I just showed you the method. Dividing hexadecimal numbers uses exactly the same method as dividing decimal numbers.

anonymous · Answer

@wiseworld, did you look at the picture (snap.jpg) I attached?

It shows the long division steps of the hex example you gave.

anonymous · Answer

i dint understand

anonymous · Answer

In decimal, the rightmost digit is the "ones" place.
The next digit is the "tens" place
The next is "hundreds", and so on.
This is the same as the rightmost digit is the 10^1 place, the next is 10^2, the next is 10^3, and so on.

In hex, the rightmost digit is also the ones place.
The next digit is the "twohundredfiftysixes" place
The next digit is the "fourthousandninetysixes" place and so on.
This is because the rightmost digit is 16^1, the next is 16^2, the next is 16^3, and so on.

This is the basis for carrying and borrowing when you manipulate numbers mathematically, regardless of the number base.

Am I explaining this to you or am I confusing you more?

anonymous · Answer

@wiseworld Do you understand now, or do you want me to try explaining further?

anonymous · Answer

You could also put in the decimal point and expand this out to 79b.92ae5b54692...

queelius · Answer

I think it would make a lot more sense for most people to first convert the base-16 numbers to base-10 instead of trying to do all of the long-division arithmetic in base-16.

Of course it's not necessary, but that'll be a lot more intuitive for most people.

queelius · Answer

So:

B9 in base 10: 9 + 11*16 = 185

57F6D = 13 + 16*6 + 16^2*15 + 16^3*7 + 16^4 * 5 = 360301

So, 360301 / 185 = 1947 remainder 106.

anonymous · Answer

Whether it's simpler or more intuitive or not isn't the issue. What he asked was how to do division using hexadecimal numbers.

queelius · Answer

He said "how to do division of hexadecimal numbers" ... I don't think that necessarily means he requires a long division process that only uses hexademical numbers.

So, anyway, I hope my answer was helpful to him.