Question

What is the equation of the line in slope–intercept form that passes through the point (0, 3) and is perpendicular to the line y = 2x – 6?

Answer 1

Remember to find the slope of the other line first. Since it's perpendicular the slope of the first line times the slope of the second line will equal -1.
So what times 2 will get you negative 1?

Answer 2

You can set this up easily by doing this:
\[2x=-1\]

Answer 3

im confused atm

Answer 4

Where did you get confused?

Answer 5

so what am i solving for first

Answer 6

y=2x-6 ?

Answer 7

Nope you don't need any part of that formula except for the slope of that formula. Which that slope is equal to 2 right?

Answer 8

\[2x+y-3=0\]

Answer 9

yes

Answer 10

Alright since that slope is perpendicular to the other slope. You just need to multiple 2 times some number to get negative 1.
So 2x=-1 what do you get for x?
-1/2 right?

Answer 11

\[x-2y-6=0\]

Answer 12

okay i gotcha so far

Answer 13

is the answe \[x-2y-6=0 ?\]

Answer 14

y=-1/2x+3 ?

Answer 15

Alright that -1/2 is the new slope of the line.
So put it in slope intercept form you have
y=-1/2x+b
correct?
now all you have to do is plug in 0 for x and 3 for y
so you get 3=0+b
meaning your b value is 3
So the answer to the problem is
Y=-1/2x+3

Answer 16

thank you

Answer 17

Glad to help :)