Question

integrate ln(x+1)

Answer 1

you can use integration by parts

Answer 2

integral = xln(x+1) - integral [ (x) 1/(x+1)] dx

Answer 3

I don't get how you got that. Like I figured it would be lnx+ln1 :\

Answer 4

i have two function 1* ln(1+x)


http://en.wikipedia.org/wiki/Integration_by_parts

Answer 5

one function is 1 and another is ln(1+x)

Answer 6

so you are using the formula uv-integral(udu)
but I don't understand how you got 1

Answer 7

for integration by parts i need two functions
ln(1+x) as such is one function
so i did 1*ln(1+x) (because multiplication by one doesn`t alter the integral)

so 1st function is 1 and second ln(1+x) and then apply integral by parts

Answer 8

well I got for my answer is
xln(1+x)-(-ln(x-1)-x)
does that look right?

Answer 9

you got it right just a little mistake
xln(1+x) - (-ln(x-1) + x)