Question

What is ZX applied to H|0>?

Answer 1

\[|0\rangle=\binom 10\]\[X=\left(\begin{matrix}0&1\\1&0\end{matrix}\right)\]do the multiplication first, and tell me what you get

Answer 2

the result is a 2*1 matrix the upper portion is 0, the lower portion is 1

Answer 3

and what do we call that in bra-ket notation ?

Answer 4

0|0> +1|1> ???

Answer 5

yes, or just |1>
now apply\[Z=\begin{pmatrix}
1 &0 \\0
&-1
\end{pmatrix}\]to\[|1\rangle=\binom01\]

Answer 6

-|1>

Answer 7

yes

Answer 8

congrads :)

Answer 9

I should write something like that ; x|0>+y|1> as an answer. I am writing 0 for x , -1 for y and system says that it is wrong... ??

Answer 10

And remember problem has H before |0>... Is it change anything?

Answer 11

oh crap, I forgot the Hadamard, my mistake :P

Answer 12

so then, what is\[H=\frac1{\sqrt2}\begin{pmatrix}
1 &1 \\1
&-1
\end{pmatrix}\]mapped to |0> ?

Answer 13

Happy to help, I hope we can work together sometimes on this stuff, it's new to me too :)