Question

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Answer 1

\[\frac{ x^2 - 1 - x - 1 }{ x^2 - x - 2 - x - 2 }\]

Answer 2

You probably have to write it as one fraction. So you must make first new fractions with the same denominator.
In principle, you could find a new denominator, by taking the product of the old ones.
It is better, though, to first factor the left denominator. I bet x/2 will be one of the factors.

This will make the new denominator a lot simpler.

BTW what lstrassmann wrote is wrong...

Answer 3

Make that x minus 2..

Answer 4

@hibecca: x²-x-2=(x+1)(x-2). Could you come up with the new denominator?

Answer 5

@ZeHanz, you're right. I was thinking of something else

Answer 6

sorry

Answer 7

What would you do if you were asked to do this: \(\frac{5}{6}-\frac{1}{2}\)?

Answer 8

You have to find a common denominator.

Answer 9

YOu would have to change the fractions: \(\frac{5}{6}-\frac{3}{6}=\frac{5-3}{6}=\frac{2}{6}=\frac{1}{3}\)

Answer 10

Yeah, what @ZeHanz said.

Answer 11

In this case, your job turns out to be a little different.
Look at the left fraction:\[\frac{ x^2-1 }{ x^2-x-2 }\]You can factor both numerator and denominator:\[\frac{ (x+1)(x-1) }{ (x+1)(x-2) }\]Does this ring a bell?

Answer 12

@hibecca : yes! YOu are right!

The first fraction simplifies to \(\frac{x-1}{x-2}\), but this is just like the second, so subtracting them gives 0.

Answer 13

YW!
What question would that be?

Answer 14

If you change \(\frac{4}{3}\) to \(\frac{4x}{3x}\), you can add it to the first fraction:
\(\frac{10+4x}{3x}\).

Now you have \[\frac{ 10+4x }{ 3x }=\frac{ 7+x }{ 2x }\]

Cross-multiply to make a simple equation. Solve for x.

Answer 15

What makes you think it is 1/5?

Answer 16

That doesn't help you understand...
You have to do it yourself!