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OpenStudy (anonymous):

what is the molarity of a nickel (II) sulfate solution, where 47.32g NiSO4 is dissolved in enough solvent so that the final volume is 3.9 liters? HELP PLEASE

OpenStudy (jfraser):

turn those grams if NiSO4 into moles, and divide by the total volume. molarity is \[M = \frac{mol}{L}\]

OpenStudy (anonymous):

@JFraser 's got it right :)

OpenStudy (jfraser):

^^

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