9/x^2-7x+12 x=-3
plug in the x = -3 into the equation for all the x variables
i have no idea how to do this, can you help withthis one
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so the answer would be 34 rightz?
i see what you did there. thanks
do i add them?
@Ceann
if you say x = -3 then you plug it into the equation where the x variables are.. if ur trying to solve for x or something weird then no..
evaluate expression for the given value of the variable
actually the 9 is above everything in the problem
its 9 / x^2-7x+12 x=-3
Sorry about that...let's give this another go. For future reference, you can make the form of the question clearer by either using the equation tool or using parentheses to indicate fractions. I'll have it reworked shortly
Thanks
Starting with form \[\frac{9}{x^2-7x+12}\] We start by factoring the denominator into its two "roots:" \[\frac{9}{(x-3)(x-4)}\] and then substituting our x identity, x= -3, for all instances of x: \[\frac{9}{(-6)(-7)}\] Simplify the bottom, divide out the top: \[\frac{9}{42}=\frac{3}{14}\] and there's your final answer. Up to you if you want to simplify it or not.
how would i simplify that?
Simplify as in divide out into a decimal. That's the simplest fraction form you can get.
thanks can i post another?
go right ahead
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