One to one function h is defined by h(x)=(3x-4)/(-2x+9). Find h^-1, the inverse of h. Then, give the domain and range of h^-1 using interval notation.

Question

anonymous · Answer

could have sworn i answered this exact question earlier

anonymous · Answer

domain of $h$ is found by setting $-2x+9=0$ and solving for $x$

anonymous · Answer

Aleks didn't take it satellite. not sure why 
I know that the inverse is: h^-1=(9x+4)/(2x+3).  
Just need help finding the domain and range in interval notation.

anonymous · Answer

maybe it was some sort of syntax error

anonymous · Answer

you just need the domain and range of $h^{-1}$ right?

anonymous · Answer

yes

anonymous · Answer

domain is 
$$(\infty, -\frac{3}{2})\cup (-\frac{3}{2},\infty)$$

anonymous · Answer

is that what you put?

anonymous · Answer

I put (-$$(-\infty, 9/2) union (9/2, \infty)$$

anonymous · Answer

that is for the range

anonymous · Answer

man!!! No wonder

anonymous · Answer

that is the domain of $h$ and the range of $h^{-1}$

anonymous · Answer

Thanks again!

anonymous · Answer

yw