Question

Thermodynamics!!!
Consider the reaction:
2 H2O (g)-->2 H2 (g) + O2 (g)
ΔH=483.6 Kj/mol
If 2 moles of H2O (g) are converted H2(g) and O2(g) against a pressure of 1 atm at 125 degrees Celcius what is ΔE of reaction?
I did this so far:
ΔE=ΔH-RTΔn
we have 2 moles H2 and 1 mole O2, net gain is 1Mole
- (125celcius + 125)=398K
-ΔE=(483.6 KJ/mol) - (8.314 J/mol)(398K)(1.0 mole)=-2825.4 kJ???
I don't know what the correct answer is, but it is not this one. Any help on what I did wrong? I am doing this on CONNECT and I'm not getting the correct answers.

Answer 1

What is RT? ... sorry I'm really tired. Lol. Would like to help, but I can't think right now :)

Answer 2

R=8.314 J/mol
T=398K (125 celcius + 125)
Don't worry, I am he same way, but our teacher gives soo much work before tests :/

Answer 3

what level are you in? ... I feel like I know how to do this, but my brain won't work. =/

Answer 4

This is chem 2. and It's ok don't worry about it. Get some rest! Thank you for your time :)

Answer 5

Sorry =/ If I think of it I'll come back later and answer

Answer 6

No problem take your time!

Answer 7

ΔE=ΔH-RTΔn, the answer is 42