HELP! who can explain derivatives :(

let f(x)= (x^3+3x+8)^2

F'(x)=
F'(2)=

Question

HELP! who can explain derivatives :(

let f(x)= (x^3+3x+8)^2

F'(x)=
F'(2)=

anonymous · Answer

use the chain rule
get 
$$F'(x)=2(x^2+3x+8)(3x^2+3)$$

anonymous · Answer

I am very bad with derivatives. I missed the whole lesson de to being sick. can we start from the beginning?

anonymous · Answer

how do we use the chain rule?

anonymous · Answer

you have something squared
the derivative of something squared is two times something, times the derivative of something

anonymous · Answer

for example, the derivative of $\sin^2(x)$ is $2\sin(x)\cos(x)$

anonymous · Answer

the derivative of $x+\sqrt{x}+\tan(x))^2$ is 
$$2(x+\sqrt{x}+\tan(x))(1+\frac{1}{2\sqrt{x}}+\sec^2(x))$$

anonymous · Answer

okay

anonymous · Answer

so how do we begin this problem?

anonymous · Answer

to find the derivative we need to place the exponent in front... correct?

anonymous · Answer

is the derivative for f'(x) = 2X^2+6X+16?