Question

HELP! who can explain derivatives :(

let f(x)= (x^3+3x+8)^2

F'(x)=
F'(2)=

Answer 1

use the chain rule
get
\[F'(x)=2(x^2+3x+8)(3x^2+3)\]

Answer 2

I am very bad with derivatives. I missed the whole lesson de to being sick. can we start from the beginning?

Answer 3

how do we use the chain rule?

Answer 4

you have something squared
the derivative of something squared is two times something, times the derivative of something

Answer 5

for example, the derivative of \(\sin^2(x)\) is \(2\sin(x)\cos(x)\)

Answer 6

the derivative of \(x+\sqrt{x}+\tan(x))^2\) is
\[2(x+\sqrt{x}+\tan(x))(1+\frac{1}{2\sqrt{x}}+\sec^2(x))\]

Answer 7

okay

Answer 8

so how do we begin this problem?

Answer 9

to find the derivative we need to place the exponent in front... correct?

Answer 10

is the derivative for f'(x) = 2X^2+6X+16?