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Mathematics 18 Online
OpenStudy (anonymous):

Can someone double check my attached solution after the post to see if I correctly did the following problem? Research by Meadows, Meadows, Randers and Behrens indicates that the earth has 3.2x10^9 acres of arable land available. The world population of 1950 required 10^9 acres to sustain it, and the population of 1980 required 2x10^9 acres. If the required acreage grows at a constant percentage rate, in what year will the population reach the maximum sustainable size?

OpenStudy (anonymous):

OpenStudy (anonymous):

above is the solution I got. Can someone make sure I didn't mess up

OpenStudy (anonymous):

Directrix (directrix):

The value of t seems reasonable. The question asks: what year will the population reach the maximum sustainable size? So, would that be the year 2030, in mid-March?

OpenStudy (anonymous):

wouldnt it be 2000???

Directrix (directrix):

I looked at it this way: 1950 --> 1 * 10^9 1980 --> 2 * 10^9 2010 --> 3 * 10^9 Year X --> 3.2x10^9 where X is 50.3 years after 1980.

Directrix (directrix):

If 30 years is the doubling time, I do not think the year 2000 seems correct.

OpenStudy (anonymous):

your right, this is what I get for forgetting that 30 is the difference between 1980 and 1950. rookie mistake

OpenStudy (anonymous):

thank you sir for responding, i think expon growth scares people lol

Directrix (directrix):

Exponential growth and decay is sometimes tricky. I am checking my text for the doubling formula now because I want to review some problems I did a year or so ago. At this time of the day (night), the number of solvers here on OpenStudy is at a minimum. So, leave your question open if you like. The others can add their comments when they wake up or get back from class.

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