Chemistry
18 Online
OpenStudy (dls):
In a chemical reaction,the rate constant of backward reaction is 7.5 x 10^-4 and the eqm. constant K=15..What is the rate of forward reaction?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (dls):
\[\LARGE 1.5=\frac{7.5 \times 10^{-4}}{x}\]
OpenStudy (dls):
Is that how it will be done ?
OpenStudy (shubhamsrg):
LHS = 1/1.5
OpenStudy (dls):
??
OpenStudy (shubhamsrg):
1.5 = x/(7.5)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (shubhamsrg):
*10^something
OpenStudy (dls):
what is the formula?
OpenStudy (dls):
\[\LARGE K_c = \frac{Backward}{Forward}\]?
OpenStudy (shubhamsrg):
K = product conc./react conc.
OpenStudy (dls):
same thing :o
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (dls):
i meant that only :P
OpenStudy (shubhamsrg):
product conc directly proportional to forward reac
same for reactant conc
OpenStudy (dls):
?
OpenStudy (dls):
rate constant and eqm constant=same?
OpenStudy (shubhamsrg):
eqbm const = forward rate/backward rate
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (dls):
:/
OpenStudy (dls):
\[\LARGE A+B \rightarrow C+D\]
to [C][D]/[A][B] ? :/
OpenStudy (shubhamsrg):
ha
OpenStudy (dls):
to back/for?
OpenStudy (shubhamsrg):
hein ?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (dls):
ok nvm thanks
OpenStudy (shubhamsrg):
thanks? :O
OpenStudy (shubhamsrg):
pehli baar! :')
OpenStudy (dls):
not fully satisfied,fact samaj ke maannlia isiliye that sarcastic thx
OpenStudy (shubhamsrg):
samjh kyu nahi aya? o.O
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (dls):
ratlia bus
OpenStudy (shubhamsrg):
C+D ban na , matlab forward reacn
OpenStudy (dls):
:O
OpenStudy (dls):
le yaar :P
OpenStudy (shubhamsrg):
:'D
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (dls):
:|