100 ml of N/10 NaOH is mixed with 100ml of N/5 HCL solution and the whole solution is made up to 1 L
What is the pH of resulting solution
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OpenStudy (dls):
@yrelhan4
OpenStudy (yrelhan4):
ionic equilibrium not my thing. i'll still try. give me some time.
OpenStudy (dls):
(Y)
OpenStudy (dls):
Number of moles of NaOH=0.01
Number of moles of HCl=0.02
OpenStudy (dls):
Concentration of NaOH=0.01
Concentration of HCl=0.02
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OpenStudy (shubhamsrg):
@shubhamsrg
OpenStudy (dls):
urself?
OpenStudy (shubhamsrg):
just bookmarking myself !
OpenStudy (dls):
:D
OpenStudy (shubhamsrg):
moles of HCl left after reacting = 0.01
volume now = 1 L
molarity = 0.01 /1 = 10^(-2)
Ph = -log(10^-2)
am getting 2.
But its wrong
In case someone ( @yrelhan4 ) can catch the flaw?
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OpenStudy (dls):
nooooooooooo!
OpenStudy (dls):
i think I got it
OpenStudy (shubhamsrg):
oye oye!
tell me
OpenStudy (dls):
hold on confirming smt
OpenStudy (yrelhan4):
looks good. :P
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