Question

What is the approximate perimeter of the composite figure shown? Use three point one four for pi.

Answer 1

Can you find the area of right triangle with base 5 mi and height 5 mi?

Answer 2

no

Answer 3

Do you know the formula for area of right triangle and\or circle?

Answer 4

A=1/2xbxh or A=bxh/2

Answer 5

Circle
Area = π × r2
Circumference = 2 × π × r
r = radius

Answer 6

Good, you're right
here for the triangle b=5 mi h=5 mi
\[\frac 1 2 b\times h\]
Just plugin the values, you'll get the area of triangle

Answer 7

wat do you mean by that

Answer 8

put b=5 and h=5, then solve it to find the area of triangle

Answer 9

ok

Answer 10

so ur saying 5x5x3.14

Answer 11

Nope,
\[\text{Area of figure}=\text{Area of triangle+ Area of circle}\]
\[\text{Area of triangle}=\frac 1 2 \times 5 \times 5\ mi^2\]

Answer 12

oh ok i get 12 1/2 tho

Answer 13

Yes, you're right. Now we need to find the area of semi circle, It's diameter is 7 mi
Can you find the area?

Answer 14

A semi-circle is half of a circle and the area of a circle of radius r is pi r2.




We know that the area of a circle is:

area of a circle = pi r2

A semi-circle is half of a circle. Therefore the area of a semi-circle will be:

area of a semi-circle = 1/2 pi r2

We know that the radius is 9ft. Pi is approximately 3.14 or 22/7.

Now you just have to plug in the numbers and you will find the area!

Answer 15

What's the radius here?

Answer 16

First, let's look at the 2 dimensional region (base of solid)
Each cross-section perpendicular to the x-axis is a "strip" of length e^x - 0 = e^x

Now we can look at 3 dimensional solid
Each cross-section perpendicular to the x-axis is a semi-circle with diameter = e^x

So each cross-section has area = 1/2 (π r²) = 1/2 π (e^x/2)² = π/8 * e^(2x)

Each very thin cross section of width dx has volume = π/8 * e^(2x) dx

Integrating from x = -1 to x = 1, we get:

Volume = ∫₋₁¹ π/8 * e^(2x) dx
. . . . . . = π/16 * e^(2x) |₋₁¹
. . . . . . = π/16 (e^(2) - e^(-2))
. . . . . . = 1.4242647516

Answer 17

From where are you posting this???
It's not relevant here

Answer 18

@preetha we need to get shadow to clean up the database .....

Answer 19

@shadowfiend might need your assistance in cleaning up some database material

Answer 20

?

Answer 21

please check the users profile page for some rather inappropriate content.

Answer 22

they also seem to have a habit of editing the content out of their questions :/