Question

find all factors of x:
x cube -12x+16=0
x cube-5x square+8=0

Answer 1

\[x^{3}-12x+16=0 \]

Answer 2

\[x^{3}-5x ^{2}+8=0\]

Answer 3

@Hero

Answer 4

You can find the first factor using trial and error. Afterwards, you can find the others by solving the remaining quadratic.

Answer 5

ok like that helps..... sigh*

Answer 6

hey hero

Answer 7

\[(2)^3 - 12(2) + 16 \\= 8 - 24 + 16 \\= 8 + 16 - 24 \\= 24 - 24 \\= 0\]

so so (x - 2) is a factor. Now, divide:

\[\frac{x^3 - 12x + 16}{x - 2}\]. You will get a quadratic afterwards. Factor it to find the remaining factors.

Answer 8

you factor the top one

Answer 9

You have to divide first

Answer 10

I explained what needed to be done.

Answer 11

ok thanks for ya help even though i just cant get

Answer 12

Polynomial long division

Answer 13

@shanayduncan