How many molecules of sucrose (C12H22O11, molar mass = 342.30 g/mol) are contained in
14.3 mL of 0.140 M sucrose solution?

What I've done is set it up as

.140 M = moles / .0143 L

.140 * .0143 L = 2.002 moles C12H22)11

2.002 moles C12H22)11 * 6.022 x 10^23 molecules / 1 mol C12H22 O 11 =

1.21 x10^24 molecules but the answer is
1.21 x 10 ^ 21 so I don't know what I'm doing wrong.

Question

How many molecules of sucrose (C12H22O11, molar mass = 342.30 g/mol) are contained in
14.3 mL of 0.140 M sucrose solution?

What I've done is set it up as

.140 M = moles / .0143 L 

.140 * .0143 L = 2.002 moles C12H22)11

2.002 moles C12H22)11 * 6.022 x 10^23 molecules / 1 mol C12H22 O 11  =

1.21 x10^24 molecules but the answer is 
 1.21 x 10 ^ 21 so I don't know what I'm doing wrong.

jfraser · Answer

0.140 M * 0.0143L is not equal to 2

anonymous · Answer

oops! you're right. it's .002002 moles. That what the problem.