Question

I have the answer can someone just check to see if I'm right.
WHich of the following is f '(x) for f(x)=(ln4)^x

Answer 1

2ln(2)^x(ln(2ln(2))

Answer 2

Ididn't get that I got (ln)(ln4)^x

Answer 3

well mine is more simplified

Answer 4

do u want me to prove the answer?

Answer 5

it doesn't matter all my choices are multiple choice so if my answer is not correct I guess I don't knwo what the answer is.

Answer 6

I got (ln)(ln4)^x <-- this does not quite make sense

Answer 7

yes i know we use D operator and ur answer would be

Answer 8

yes the answer is wrong

Answer 9

ok so then what is the answer I am confussed

Answer 10

how about
ln(ln(4)) * (ln(4))^x

Answer 11

you could write ln(4) as ln(2^2) = 2 ln(2) but only if they put the answer in those terms

Answer 12

if you have the problem d/dx a^x
write a as e^(ln(a))
and a^x is e^(x ln(a))

in your case a is ln(4)

Answer 13

so then is the answwer ln(ln(ln4)^x

Answer 14

no

Answer 15

\[ \frac{d}{dx} e^{x ln(ln(4))} \]

Answer 16

what about this ln(ln4)(ln(ln4))^x

Answer 17

the ln(ln(4)) is just a constant (ugly maybe, but a constant)
so you get
\[ ln(ln(4)) e^{x ln(ln(4))} \]
but we can replace
\[ e^{x ln(ln(4))} = \left( e^{ln(ln(4))}\right)^x = (ln(4))^x\]
and the answer is
\[ ln(ln(4))(ln(4))^x \]

Answer 18

yes that is similar to the one at the top

Answer 19

so then which is right the one that phi just wrote

Answer 20

yes phi is right obvious

Answer 21

ok thanks

Answer 22

wait thoughthat is not one of my choices

Answer 23

would ln(ln4)(ln4)^x work