Question

y=(tan^-3x)^2

Answer 1

What do you want us to do with this function?

Answer 2

And can you re-type it?

Answer 3

m sorry the question is y=(tan^-1 3x)^2? find derivative of function

Answer 4

\[y=[\tan^{-1}(3x)]^2\]
Is this the one?

Answer 5

Have you done derivatives of inverse trigonometric functions?

Answer 6

yes, but calculus is extremely hard for me..

Answer 7

So we use the Arctangent rule for derivatives, Power rule, and Chain rule.\[y'=2[\tan^{-1}(3x)]*\frac{ 1 }{ 1+(3x)^2 }*3 \rightarrow y'=\frac{ 6[\tan^{-1}(3x)] }{ 1+9x^2 }\]@engdorj09

Answer 8

@engdorj09