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Calculate the number of moles of aluminun are required when 1.80 mol of Fe is produced in the following reaction.
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What is the reaction???
@cntrywrtr
Okay .. for every 2 mol of Al 3 mol Fe are produced right?? ... You're given 1.80 mol FE and you need mol Al. This is your set up.............\[1.80 mol FE \times \frac{ 2 mol Al }{ 3 mol FE }= 1.20 mol AL \]
Does that make sense?
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