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factor m^3+n^3
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\[m^3+n^3=(m+n)(m^2-mn+n^2)\]
ok got it,, so will the sigs in the trinomial always alternate the + and the -??
so th sign in (m <sign> n) is whatever sign is in the m^3 <sign> n^3 and then the first sing in the (m^2 <sign> mn +n^2) is opposite
i think i am finally getting this tytytytyyt!!!!!
\[m^3+n^3=(m+n)(m^2-mn+n^2)\\m^3-n^3=(m-n)(m^2+mn+n^2)\]
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no problem :)
1 more ?? pls,,, x^2 + y^2 factors into (x-y) (x+y) correct??
\[x^2-y^2=(x+y)(x-y)\] and sometimes this one is useful: \[x^2+y^2=(x+y)^2-2xy\]
kk tytyty
no problem :)
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