In how many ways can 3 cards be selected from a 12-card deck if the selected cards are not returned to the deck?
I know the first step is 12C3 (c=combination) but what's my next step?

Question

In how many ways can 3 cards be selected from a 12-card deck if the selected cards are not returned to the deck? 
I know the first step is 12C3 (c=combination) but what's my next step?

anonymous · Answer

compute $_{12}C_3$ via 
$$\frac{12\times 11\times 10}{3\times 2}$$

anonymous · Answer

cancel first, multiply last

anonymous · Answer

I know that then the answer is 220, but I feel like there is more to the question

anonymous · Answer

What about the part of the question that says "if the selected cards are not returned to the deck"? Is that there just to trick me? @satellite73

raden · Answer

in selecting progress, one by one or direct 3 cards ?

anonymous · Answer

Selecting three at a time

raden · Answer

if a time,dont look returned or not :)

anonymous · Answer

"if the selected cards are not returned to the deck" just  means  that  the total of  cads  will  be less than  before

anonymous · Answer

I understand that but after 12C3 then what do I do?

anonymous · Answer

@RadEn @Luis_Rivera @satellite73

raden · Answer

do u  find the probability of that event ?

anonymous · Answer

That's irrelevant 
It's not asking me to find the probability

raden · Answer

well, it has cleared from u and satellite :)

kropot72 · Answer

Your question is basically the same as "How many ways can three people be selected from a group of twelve people?"
In general if the question states "selected" a combination is appropriate whereas if "arrangements" is stated a permutation applies.
Therefore, as already answered, the solution to your question is 12C3. No other step is needed after that calculation