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Find the derivative with respect of x ln(6((cos^5)x))
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use the chain rule :)
derivative of cos is -sin derivative of u^5 is 5u^4 derivative of ln(u) is 1/u
So would the answer be (30cosx^4*-sinx)/(6cos^5x)
yes, but actually it can simplied again 30/6 = 5 cos^4 x / cos^5 x = 1/cosx so, what's the final answer ?
(-5sinx)/cosx ?
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yup, simply again :) sin/cos = tan
Thank You so much!(:
it can be -5tanx, right ? you're welcome :)
Well I typed in (-5sinx)/cosx and it was correct(:
great :)
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