Question

What is the 6th term of the geometric sequence where a1 = -625 and a2 = 125?

Answer 1

In order to find the nth term of a geometric sequence, use the following
\[r = \frac{a_2}{a_1}\]
Then apply the general nth term rule
\[a_n=ar^{n-1}\]
where a is the first term

Answer 2

and n=6

Answer 3

with all these information you should get the required answer...

Answer 4

Hmm

Answer 5

.2

Answer 6

May you help with another?

Answer 7

ok sure

Answer 8

r=(125/(-625))=?

Answer 9

-.02

Answer 10

.2*

Answer 11

-.2

Answer 12

and a=a1

Answer 13

r = -0.2, and a = -625

Answer 14

n=6

Answer 15

are u following all u need now is to use the calculator

Answer 16

@tinaballerina are u following

Answer 17

isnt the answer -.2?

Answer 18

-0.2
0.2
-0.04
0.04
these are the options.

Answer 19

you should plug the numbers i gave u in:
\[a_n=ar^{n-1}\]

Answer 20

=-625(-0.2)^(6-1)

Answer 21

i don't have a calculator now, but check the answer with urs

Answer 22

ugh i waas right before it was .2

Answer 23

good then

Answer 24

http://openstudy.com/study#/updates/5136cef8e4b093a1d94ab397 , if you may

Answer 25

This was incorrect (just took the test) :)